Anyone out there can help to solve the following Pri 3 problem sum?

I need the steps and answer.

Thanks in advance....

A,B and C shared $120. A received $10 more than B, B received $10 more than C. How

much A received?

A will have 20 more than C. B having 10 more than C. So you just divide (120-30)/3 = 30.

Add 20 to 30, A will have 50. B = 40. C = 30

Can solve using algebra, but not sure if relevant?

Assume the amount that C receives is $X. So the following:

C = $X

B = $X + $10

A = $X + $10 + $10

Total $120 = 3X + $30,

3X = $120 - $30 = $90,

Thus X = $90 / 3 = $30.

A = $X + $10 + $10 = $30 + $10 + $10 = $50.

Thank u very much!!!!1

Can solve using algebra, but not sure if relevant?

Assume the amount that C receives is $X. So the following:

C = $X

B = $X + $10

A = $X + $10 + $10

Total $120 = 3X + $30,

3X = $120 - $30 = $90,

Thus X = $90 / 3 = $30.

A = $X + $10 + $10 = $30 + $10 + $10 = $50.

Primary school maths homework cannot use algebra to solve even if the answer is correct...

Primary school maths homework cannot use algebra to solve even if the answer is correct...

yup, that's what I recalled too. you might find it stupid but, that's the way to train when they are not ready for algebra yet.

I thought we learn algebra at some point in primary school? Think is pri 3 or 4 right?

I know for me I only learn algebra very late during my time, but I thought I just saw some primary school assessment books got algebra leh...

nope, algebra is only available in secondary school if i'm not wrong....

come on, the purpose of that exercise is not to find the best way to solve problem, it's to train their brain to think lah. that's the basic foundation.

I also tort we learnt algebra in Pri sch.....till my colleague say Pri 3 students

not yet learn...I also dunno cos I hv no children...

Nevertheless...really thanks...I can help my colleague out..haha